I/O Operations Q. 6: Scientist Game

QUESTION DESCRIPTION 

Armstrong was one of the great scientist.

The Indian council decided that we need to assign some number as a gift to the great scientist.

There was a suggestion given by the Indian Council. If the sum of cube of each number is again equal to the number then they decided that they can assign the number to the great scientist.

Kindly help the Indian Council to complete the task by writing a simple logic.

Refer sample Inputs and Outputs.

Input 1: 153

Output: Give to Scientist Armstrong

Reason((1*1*1 + 5*5*5 3*3*3=153) which is equal to the number)

Input 2: 134

Output: Don't Give to Scientist Armstrong

Reason((1*1*1 + 5*5*5 2*2*2=134) which is not equal to the number )










#include <iostream>
using namespace std;

int power(int, int);

int main()
{
   int n, sum = 0, temp, remainder, digits = 0;

   
   scanf("%d", &n);

   temp = n;
   // Count number of digits
   while (temp != 0) {
      digits++;
      temp = temp/10;
   }
   
   temp = n;
   
   while (temp != 0) {
      remainder = temp%10;
      sum = sum + power(remainder, digits);
      temp = temp/10;
   }

   if (n == sum)
      printf("Give to Scientist Armstrong\n");
   else
      printf("Dont Give to Scientist Armstrong\n");

   return 0;
}

int power(int n, int r) {
   int c, p = 1;
   
   for (c = 1; c <= r; c++)
      p = p*n;
     
   return p;  

}